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Path: utzoo!utcs!lsuc!pesnta!amdcad!cae780!gordon
From: gordon@cae780.UUCP (Brian Gordon)
Newsgroups: net.games.trivia
Subject: Re: Dumb trivia because I am bored.
Message-ID: <434@cae780.UUCP>
Date: Thu, 7-Feb-85 16:33:00 EST
Article-I.D.: cae780.434
Posted: Thu Feb  7 16:33:00 1985
Date-Received: Fri, 8-Feb-85 09:49:03 EST
References: <1594@gondor.UUCP> <448@topaz.ARPA> <7923@brl-tgr.ARPA> <868@ut-sally.UUCP>
Reply-To: gordon@cae780.UUCP (Brian Gordon)
Distribution: net
Organization: AMDCAD, Sunnyvale, CA
Lines: 23
Summary: 

In article <868@ut-sally.UUCP> preston@ut-sally.UUCP (Randal Preston) writes:
>Nope!  It's got to be *at least* 28 years
>	      (7 days/week * 4 years/leap-year cycle)
>
>But I also think that century-marks throw a kink into things, so I'd say
>an integral number of centuries.  (10 centuries?  Doesn't something special
>happen on the years 1000, 2000, 3000, etc.?)

I presume this was about the number of different calendars.  If so, I
disagree.  The "year in the leap-year cycle" is not involved except for
the leap-year yes/no.  A year which is not a leap-year, and starts on, for
example, a Wednesday, will have the same calendar no matter whether the
next leap-year is 1, 2 or 3 years ahead.  It STILL looks like 7 leap-year
calendars, 7 non-leap-year calendars, 14 total calendars.

As for centuries (for which the definition of leap-century is simple enough),
it is still either leap or non-leap, and starts on one of the 7 days!

FROM:   Brian G. Gordon, CAE Systems
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