Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83; site cbneb.UUCP Path: utzoo!watmath!clyde!cbosgd!cbsck!cbneb!adm From: adm@cbneb.UUCP Newsgroups: net.games.trivia Subject: Re: Dumb trivia because I am bored. Message-ID: <2940@cbneb.UUCP> Date: Thu, 7-Feb-85 09:22:09 EST Article-I.D.: cbneb.2940 Posted: Thu Feb 7 09:22:09 1985 Date-Received: Fri, 8-Feb-85 03:21:57 EST Sender: adm@cbneb.UUCP Organization: AT&T Bell Laboratories, Columbus, OHIO Lines: 27 Nf-ID: #R:gondor:-159400:cbnap:14000001:000:1030 Nf-From: cbnap!tjl Feb 7 08:50:00 1985 /* BLANK line or Blankity-blank line if you prefer */ > 2) How many calanders do you need to have a 'perpetual' calander? > (Ie: For all eternity you would need no more than X calanders > to represent whatever year you may be in.) The proposed answer of fourteen calanders[sic] works for recent centuries and the foreseeable future; that is a 1/1/** for each day of the week plus another seven for leap years. However, others are needed for a perpetual calendar. For example, a special one is needed for 1752. September of that year is missing eleven days. Try cal 9 1752 on your UNIX(c) system. That should add over a thousand contiguous years to the perpetual calendar. If I remember my ancient history correctly, the caesars Augustus and Julius both 'stole' a day from February to make their months longer. I'm sure that would add several calendars for both the transition years and however they looked before that. (Aren't leap years a fairly new invention?) Answer: 15 + whatever the romans needed.