Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10 5/3/83; site umcp-cs.UUCP Path: utzoo!watmath!clyde!floyd!harpo!seismo!rlgvax!cvl!umcp-cs!james From: james@umcp-cs.UUCP Newsgroups: net.math Subject: Re: what is i raised to the ith power? Message-ID: <5043@umcp-cs.UUCP> Date: Thu, 9-Feb-84 18:21:43 EST Article-I.D.: umcp-cs.5043 Posted: Thu Feb 9 18:21:43 1984 Date-Received: Fri, 10-Feb-84 07:15:11 EST References: <680@linus.UUCP> Organization: Univ. of Maryland, Computer Science Dept. Lines: 18 Easy, it is: __ -|| / / 2 e (which is exp(-pi/2)). The way to get this result is: Any complex number C may be written as exp(a+bi) for some real a,b. i Then exp(a+bi) = exp((a+bi) * i) = exp(ai - b). (Using exponent rule.) i So consider C = i. i = exp(0 + pi/2) ==> i = exp(0i - pi/2) = exp(-pi/2). The actual value is approximately .20787958 --Jim