Relay-Version: version B 2.10 5/3/83; site utzoo.UUCP Posting-Version: version B 2.10.1 6/24/83; site dartvax.UUCP Path: utzoo!linus!decvax!dartvax!johnc From: johnc@dartvax.UUCP (johnc) Newsgroups: net.puzzle,net.math Subject: Strange Addition (***** Spoiler *****) Message-ID: <715@dartvax.UUCP> Date: Sun, 12-Feb-84 15:38:34 EST Article-I.D.: dartvax.715 Posted: Sun Feb 12 15:38:34 1984 Date-Received: Tue, 14-Feb-84 01:28:53 EST Organization: Dartmouth College Lines: 18 The answer to that is easy. If you do any computing, it makes you think in bases other thn decimal, which this problem is. if you add up the right column and subtract the 'answer' from it, you most likely have the base that is needed for the rest of the problem. Just to check, use that base to figure the other columns out. This problem comes out to be: 161 7 134 7 145 7 ---- 503 7 QED